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I’ve put the bottom-of-the-frame interrupt first here. This is mainly out of laziness—since this is the interrupt that restores the display for the next frame, putting it first means that it will also end up being the screen initialization code.

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For 4 points, that is (1/2)3=1/8(1/2)^3 = 1/8(1/2)3=1/8, the same 12.5% we measured earlier. There is one such event for each of the NNN points, so we have NNN events each with probability 1/2N−11/2^{N-1}1/2N−1.

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